Natural Rubber Grading
Grade 9 mathpower 9 westerncoast review question?
1 The length of a rectangle is 3 meters higher than the perimeter is Width.The 26m. What are Tye dimension of the rectangle? # 2 The length of the side of a triangle are 3 consecutive numbers.The perimeter of the triangle is 126 m How long each side? # 3 The Mass is a synthetic material in a hockey puck is 9 times the mass of the natural regulation rubber.A puck has a mass of 170 g What mass Natural Rubber is in a hockey puck? # 4 The sum of 2 plus number is the first time 4 51.Twice 128.what are the second is the number? Please help me !!!!!!!!!!!
1. L is the length and width than W. The perimeter is L + L + W + W = W = 2L 2 26 26 We also know the relationship between L and LW = W 3 So we have 2 equations and 2 unknowns, we can use substitution. Substitute L in the equation of the perimeter: 2 (W 3) 2 W W 2 W = 23 +6 +2 = 26 4 W 4 W 6 = 23 = 17 W = 17 / 4 Now that we know we can solve for W 17/4-3 LL = L = 5 / 4 # 2 We will call the sides of the triangle a, b, and c. We know that the perimeter is A + B + C = 126 and we know that the sides are consecutive numbers. This means that B = A 1 B and C = 1 Once again, we have 3 equations and 3 unknowns. Substitute: A + (A + 1) + (B +1) = 126 A + (A + 1) + (A +2) = 126 = 126 3 3A Resolving # 3 for A. Let's call the mass of natural rubber and synthetic NS = S. * N 9 The total mass of 170g S + N = 170 have 2 equations and 2 unknowns, solving as before. # 4 Let's call the first number X and second Y X + Y = 51 Y = 2X 4 128 Resolve.
BRM V17-48 PVD Ti/SS Racing Automatic 48mm – Rob Sacco aka Robrobin
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